Question #291595

An infinitely long conductor has a circular loop tangent to it. A current of 5 A flows through the conductor. Find the radius of the loop if the intensity of the magnetic field at its centre is 41 A/m.



1
Expert's answer
2022-01-30T15:27:26-0500

We know that

B=μ0ni2rB=\frac{\mu_0 ni}{2r}

Now B=μ0HB=\mu_0H

Both equation equal

μ0H=μ0ni2r\mu_0H=\frac{\mu_0 ni}{2r}

H=ni2rH=\frac{ni}{2r}

Put n=1

i=5A

H=41A/m

Put value

41=1×52×r41=\frac{1\times5}{2\times r}

r=582=0.060mr=\frac{5}{82}=0.060m


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