Answer to Question #291011 in Electricity and Magnetism for AUGUSTINE8

Question

Two long parallel wire are 10cm carrying a current of 6A and 4A. Calculate the force of acting on a 100cm length of

Answer 1

$F=\frac{μ_02I_1I_2l}{4\pi d}$

Where

$I_1=6A$

$I_2=4A$

$d=10×10^{-2}M =0.1M$

$l=100×10^{-2}M =1M$

$μ_0=4\pi×10{^-7}$

$F=\frac{4\pi×10^{-7}×2×6×4×1}{4\pi ×0.1}=4.8×10^{-5}N$