Question #290841

Spheres A and B have the same initial positive charge qO.The magnitude of the repulsive electric force between the two spheres is 14.4 N when separated by a distance of 0.03 m.



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a) Find the initial q0



b)The spheres are then allowed to touch each other and then separated.Find the electric force between them if the radius of sphere A is three times that of sphere B.

1
Expert's answer
2022-01-26T17:47:18-0500

(A)F=14.4N

d=0.03m

Force

F=kq1q2r2F=\frac{kq_1q_2}{r^2}

14.4=9×109×q020.03214.4=\frac{9\times10^9\times q_0^2}{0.03^2}

1.44×1012=q021.44\times10^{-12}=q_0^2

q0=1.2×106Cq_0=1.2\times10^{-6}C

Charge

q0=q1=q2=1.2×106Cq_0=q_1=q_2=1.2\times10^{-6}C

Part(b)

According to question


qr=q0q3r\frac{q}{r}=\frac{q_0-q}{3r}

3q=q0q3q=q_0-q

4q=q04q=q_0

q=q04q=\frac{q_0}{4}

Now force

F=kq1q2r2F=\frac{kq_1q_2}{r^2}

q1=3q04,q2=q04q_1=\frac{3q_0}{4},q_2=\frac{q_0}{4}

F=k×3q04×q040.042F=\frac{k\times\frac{3q_0}{4}\times\frac{q_0}{4}}{0.04^2}


F=9×109×3×1.2×106×1.2×10616×0.0016=2.7NF=\frac{9\times10^9\times3\times1.2\times10^{-6}\times1.2\times10^{-6}}{16\times0.0016}=2.7N


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