Four equal-magnitude point charges (3.0 C) are placed at the corners of a square that is 40 cm on a side. Two, diagonally opposite each other, are positive, and the other two are negative. Find the force on either negative charge.
F=2F1+F2=2kq2r2−kq22r2=3kq22r2=760⋅109 N.F=2F_1+F_2=2\frac{kq^2}{r^2}-\frac{kq^2}{2r^2}=\frac{3kq^2}{2r^2}=760\cdot 10^9~N.F=2F1+F2=2r2kq2−2r2kq2=2r23kq2=760⋅109 N.
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