Question #284923

How much force is repelled by two pieces of copper, each weighing 1 g, located at a distance of 100 km, if all the atoms of one and the other piece are "taken away" by electrons, ie all atoms in the samples are completely ionized ?, 




Expert's answer

Determine how many atoms of copper there are in 1 g of copper:


N=nNA=mMNA.N=nN_A=\dfrac m{\Mu}N_A.


The charge of each atom, therefore, is


q=eZN=emMZNA.q=eZN=e\dfrac m{\Mu}ZN_A.


The force between the charges:


F=14πϵ0q2r2=14πϵ0(emZNA)2(Mr)2, F=1.718109 N.F=\dfrac 1{4\pi\epsilon_0}·\dfrac{q^2}{r^2}=\dfrac 1{4\pi\epsilon_0}·\dfrac{(emZN_A)^2}{(\Mu r)^2},\\\space\\ F=1.718·10^9\text{ N}.


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