Question #28377

two point charges A and B are R distance apart. a third point charge placed on the perpendicular bisector at a distance d from the centre will experience maximum electrostatic force when...

Expert's answer

QUESTION:

Two point charges A and B are R distance apart. a third point charge placed on the perpendicular bisector at a distance d from the centre will experience maximum electrostatic force when...

SOLUTION:


Let's assume that all charges are similar. Hence, total force, acting on the third charge, according to the law of cosines is


Ftotal=F12+F222F1F2cosαF _ {t o t a l} = \sqrt {F _ {1} ^ {2} + F _ {2} ^ {2} - 2 F _ {1} F _ {2} \cos \alpha}


So, maximum total force is reached when


cosα=0\cos \alpha = 0


or


α=90\alpha = 9 0 {}^ {\circ}


Or when triangle ABC is a right triangle, and angle ACB=90\mathrm{ACB} = 90{}^{\circ}

ANSWER

So, maximum total force is reached when


cosα=0\cos \alpha = 0


or


α=90\alpha = 9 0 {}^ {\circ}


Or when triangle ABC is a right triangle, and angle ACB=90\mathrm{ACB} = 90{}^{\circ}

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