A long straight copper wire of radius R carries a free current I. The current is distributed uniformly over the cross-section of the wire. Find the magnetizing field H outside and inside the wire
H1=0,H_1=0,H1=0,
H2=Bμ0=μI2πR.H_2=\frac B{\mu_0}=\frac{\mu I}{2\pi R}.H2=μ0B=2πRμI.
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