Question

A loop of area 8.0cm is in constant magnetic field of B 0.15 T what is the magnetic flux through the loop when the loop is perendicular to the field?

Answer 1

Magnetic flux is given as follows (https://en.wikipedia.org/wiki/Magnetic_flux):

$$\Phi = BS\cos \theta$$

where $B = 0.15T$ is the mgnetic field, $S = 8cm^2 = 8\times 10^{-4}m^2$ is the area of the loop, and $\theta =0$ is the angle between loop's perpendicular and magnetic field. Thus, obtain:

$$\Phi = 0.15\cdot 8\times 10^{-4} = 1.2\times 10^{-4}Wb$$

Answer. $1.2\times 10^{-4}Wb$.