Answer to Question #277278 in Electricity and Magnetism for danieal

Question #277278

A proton moving with a velocity of 3 × 10^8 ms-1 perpendicularly in a magnetic field strength X T. Given that the force of the proton received is 4.8 × 10^-13 N. Find the value of X.

Expert's answer

"F=qvB,\\implies"

"B=\\frac F{qv}=0.01~T."

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