Answer to Question #271108 in Electricity and Magnetism for Puge

Question

a dynamo delivers 30.0 a at 120 v to an external circuit when operating at 1200 rpm. what torque is required to drive the generator at this speed if the total power losses are 400 W?e

Answer 1

I = 30.0 A

V = 120 V

$P = IV = 30.0 \times 120 = 3600 \;W$

Power loss = 400 W

Total power output = 3600 + 400 = 4000 W = 4 kW