Question #269698

 If the refractive index of a liquid is 4/3. The critical angle for the liquid is ____________?


1
Expert's answer
2021-11-25T09:44:01-0500

According to Snell's law

C=sin1(1/n)C= sin -1 (1/n)

Where :

C=C= Critical angle

n=n= Refractive Index

C=sin1(1/(4/3))C= sin -1 (1/(4/3))

C=C= 48.590



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