Question #268026

a dielectric material has relative permittivity 18 and loss tangent 10^-3 at 100 MHz find the conductivity of the medium

1
Expert's answer
2021-11-18T15:01:59-0500

σ=wϵrϵ0tanϕ\sigma=w \epsilon_r\epsilon_0tan\phi

f=108hzϵr=18f=10^8hz\\\epsilon_r=18

Put value


σ=2π×108×18×8.85×1012×103=1.0×104mho/m\sigma=2\pi\times10^8\times18\times8.85\times10^{-12}\times10^{-3}=1.0\times10^{-4} mho /m


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