Answer to Question #262202 in Electricity and Magnetism for cPHA

Question

A rectangular loop of wire is ℓ

ℓ = 800 mm

mm long and w

w= 500mm

mmwide. You bend the ℓ

ℓ sides into a semicircle while keeping the w

w sides straight, as shown in (Figure 1), and then move the curved loop at speed v

vv= 0.900m/s

m/s into a uniform magnetic field of magnitude B

BB= 0.600T

T. One of the sides labeled w

w is the leading edge of the moving loop, and the magnetic field direction is perpendicular to the plane CDEF What is the value of the emf induced in the loop?

Answer 1

l = 800 mm = 0.8 m

W = 0.5 m

v = 0.90 m/s

B = 0.60 T

For the value of emd induced in the loop is E

$E = B \times v \times W \\ E = 0.60 \times 0.90 \times 0.5 \; V \\ E = 0.27 \; V$

The value of emf induced is 0.27 V

Using Lenz's law the direction of current is D to C the direction of current is CFED