φ=φ1−φ2=kr(∣q1∣−∣q2∣)=9⋅103 V=9 kV.\varphi=\varphi_1-\varphi_2=\frac kr(|q_1|-|q_2|)=9\cdot 10^3~V=9~kV.φ=φ1−φ2=rk(∣q1∣−∣q2∣)=9⋅103 V=9 kV.
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