Question

Find the emf induced in a 0.1-H coil when the current in it is changing at the rate of 80 A/s.

Answer 1

The expression for the induced emf:

$E = -L \times \frac{di}{dt}$

Inductance of the coil= L = 0.1 H

Rate of change of the current in the coil $= \frac{di}{dt} = 80 \;A/s$

$E = -0.1 \times 80 \; Volt = -8.0 \; V$

Therefore, induced emf in the coil = 8.0 Volt