Question #259383

How fast should a wire 20 cm long be moved through a 0.05-T magnetic field for an emf of 1 V to appear across its ends? 


1
Expert's answer
2021-11-07T19:58:31-0500

E=BlvsinθE=Blvsin\theta

θ=90°l=0.20mB=0.05TE=1V\theta=90°\\l=0.20m \\B=0.05T\\E=1V

Put value

v=EBlsinθv=\frac{E}{Blsin\theta}

v=10.05×0.2×sin90°v=\frac{1}{0.05\times0.2\times sin90°}

v=100010=100m/secv=\frac{1000}{10}=100m/sec


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