How fast should a wire 20 cm long be moved through a 0.05-T magnetic field for an emf of 1 V to appear across its ends?
E=BlvsinθE=Blvsin\thetaE=Blvsinθ
θ=90°l=0.20mB=0.05TE=1V\theta=90°\\l=0.20m \\B=0.05T\\E=1Vθ=90°l=0.20mB=0.05TE=1V
Put value
v=EBlsinθv=\frac{E}{Blsin\theta}v=BlsinθE
v=10.05×0.2×sin90°v=\frac{1}{0.05\times0.2\times sin90°}v=0.05×0.2×sin90°1
v=100010=100m/secv=\frac{1000}{10}=100m/secv=101000=100m/sec
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