1. A wire that is 40 cm long is parallel to a 0.67-T uniform magnetic field. There is 5.6 A current through the wire. How much force acts on the wire?
F=BIL
Where B is magnetic field, I is current and L is length.
F=0.67×5.6×0.4=1.5NF=0.67×5.6×0.4=1.5NF=0.67×5.6×0.4=1.5N
Therefore Force=1.5N
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