Parallel connection solve for the total capacitance, total charge and individual charge.
C1 = 6.31 x 10^-12
C2 = 3.75 x 10^-12
C3 = 7.23 x 10^-12
V = 1400 V
C=C1+C2+C3=17.29⋅10−12 F,C=C_1+C_2+C_3=17.29\cdot 10^{-12}~F,C=C1+C2+C3=17.29⋅10−12 F,
q=CU=24.2⋅10−9 C,q=CU=24.2\cdot 10^{-9}~C,q=CU=24.2⋅10−9 C,
q1=C1U=8.8⋅10−9 C,q_1=C_1U=8.8\cdot 10^{-9}~C,q1=C1U=8.8⋅10−9 C,
q2=C2U=5.3⋅10−9 C,q_2=C_2U=5.3\cdot 10^{-9}~C,q2=C2U=5.3⋅10−9 C,
q3=C3U=10.1⋅10−9 C.q_3=C_3U=10.1\cdot 10^{-9}~C.q3=C3U=10.1⋅10−9 C.
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