Answer to Question #258406 in Electricity and Magnetism for Lorenz

Question

Series connection solve for the total capacitance, total charge and individual voltage.

C1 = 3.5 x 10^-12

C2 = 2.4 x 10^-12

C3 = 1.13 x 10^-12

V = 1700 V

Answer 1

$C=\frac{C_1C_2C_3}{C_1C_2+C_2C_3+C_2C_3}=0.63\cdot 10^{-12}~F,$

$q=CU=1.07\cdot 10^{-9}~C,$

$U_1=\frac q{C_1}=306~V,$

$U_2=\frac q{C_2}=446~V,$

$U_3=\frac q{C_3}=948~V.$