Find the electric potential of a point located at a distance of 0.8 m from a charge of q=8µC
Electric potential
V=kQrV=\frac{kQ}{r}V=rkQ
V=9×109×8×10−60.8=9×104VV=\frac{9\times10^9\times8\times10^{-6}}{0.8}=9\times10^{4}VV=0.89×109×8×10−6=9×104V
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