Answer to Question #257130 in Electricity and Magnetism for zuzu

Question #257130

a) Find the potential energy at the midpoint from a line that joins charge -15 x10-6C with a charge +13 x10-6C that is located 0.08m from first charge.

b) A charge +55 x10-9C is 0.08m at left of a charge -16 x10-9C. Find the potential at a point located 400cm left from charge q=16 x10-9C.



1
Expert's answer
2021-10-26T17:17:56-0400

a)


"E=-(9\\cdot10^{9})\\frac{(15\\cdot10^{-6})(13\\cdot10^{-6})}{0.08}=-22\\ J"

b)


"V=(9\\cdot10^{9})\\frac{(55\\cdot10^{-6}-16\\cdot10^{-6})}{0.04}=8.8\\cdot10^{6}\\ V"


Need a fast expert's response?

Submit order

and get a quick answer at the best price

for any assignment or question with DETAILED EXPLANATIONS!

Comments

No comments. Be the first!

Leave a comment

LATEST TUTORIALS
New on Blog
APPROVED BY CLIENTS