Question

1. Determine the peak frequency deviation for a FM modulator with a deviation sensitivity of 12 kHz/V  and a peak modulating signal of 9V.

Answer 1

We know that

Voltage $V=V_0sin(wt)$

$V=9sin(24\pi t+\Phi)$

Peak frequency deviation

$n=\frac{12}{\sqrt2}=6\sqrt{2}Hz$