Question #24862

How much force is exerted between two charged objects that are separated by a distance of 1.5 meters if both objects have a charge of +3.0C?

Expert's answer

Question 24862

The expression for Coulomb force is F=kq1q2R2|F| = \frac{k q_1 q_2}{R^2} , where k=8.988109Nm2C2k = 8.988 \cdot 10^9 N m^2 C^{-2} , R=1.5mR = 1.5m , q=3Cq = 3C . Plugging in these values into this formula, obtain:


F=8.988109Nm2C23C3C(1.5)2m2=3.61010N.| F | = \frac {8 . 9 8 8 \cdot 1 0 ^ {9} N m ^ {2} C ^ {- 2} 3 C \cdot 3 C}{(1 . 5) ^ {2} m ^ {2}} = 3. 6 \cdot 1 0 ^ {1 0} N.

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