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Answer to Question #2434 in Electricity and Magnetism for Ian Kinyanjui
Question #2434
What is the force per meter of length of a straight wire carrying a 3.40A current when placed at an angle of 40° to a 0.75T unifotm magnetic field?....(please help me by showing the working)
Expert's answer
Sinse F = B I L sin α, force per meter is
F/L = BI sin α = 0.75 * 3.4 * sin 40 = 1.64 N/m.
F/L = BI sin α = 0.75 * 3.4 * sin 40 = 1.64 N/m.
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