Question #239636

The primary winding of the welding transformer has 1000 turns and the secondary winding 110 turns. It is connected to the mains at a voltage of 230 V, giving a secondary current of 120 A. Assume an ideal welding transformer.

a) What is the primary current? How big a fuse should there be behind the socket to which the welding transformer is connected - which of the 10 A, 16 A or 20 A fuses is large enough?

b) What is the secondary voltage?

c) Why is the secondary current in the welding transformer desired high?


1
Expert's answer
2021-09-21T12:02:12-0400

Gives

N1=1000N2=110V1=230VN_1=1000\\N_2=110\\V_1=230V

I2=120AI_2=120A

Part(b)

V1V2=N1N2V2=N2N1×V1\frac{V_1}{V_2}=\frac{N_1}{N_2}\\V_2=\frac{N_2}{N_1}\times V_1



V2=1101000×230V_2=\frac{110}{1000}\times 230

V2=25.3V

Part(A)

I1=N2N1×I2I_1=\frac{N_2}{N_1}\times I_2

I1=1101000×120=13.2AI_1=\frac{110}{1000}\times 120=13.2A

Part(c)

big a fuse should there be behind the socket to which the welding transformer is connected 10 Amp


I2=120AI_2=120A then turn N2=110N_2=110

High current flow in low turn transformer

Iα1NI\alpha \frac{1}{N}

Current inversely proportional to turns


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