Answer to Question #227691 in Electricity and Magnetism for brown

Question

we keep the switch at position x for a sufficient time and thereafter (at t0) connect it to Y, in the circuit shown below.

what amount of current will be measured through the resistor after 5.0 micro-second from t0, if V=9v, R=10 and C=1

Answer 1

The voltage across the capacitor will be

$$V_C=V_s\big(1-e^{-t/(RC)}\big).$$

The current:

$$I=\frac{V_C}{R}=\frac{V_s\big(1-e^{-t/(RC)}\big)}{R}=0.35\text{ A}.$$