Question #226490

An electric field is generated in between two parallel hundred square meter electrodes that are separated by a distance of 2 centimeters.
We have the one plate charged to 5.0 nano coulomb and the other one. Exactly equal but opposite.

An additional square shaped surface is placed in between plates

Expert's answer

An electric field is generated in between two parallel hundred-square-centimetre electrodes that are separated by a distance of 2 cm. We have the one plate charged to 5.0 nano-Coulombs and the other one exactly equal but opposite. An additional "square-shaped" surface ( with side length of a centimetre) is placed in between the plates and rotated such that it makes an angle of pi/4 radians with the electric field. Determine the flux of the electric field through the square surface.


The flux is:

Φ=EScosθ, (S=1 cm2),\Phi=ES'\cos \theta,~(S'=1~cm^2),

the electric field is:

E=Ud=qCd=qddε0S=qε0S, (S=100 cm2, q=q1q2=5(5)=10 nC),E=\frac Ud=\frac q{Cd}=\frac{qd}{d\varepsilon_0 S}=\frac q{\varepsilon_0 S},~(S=100~cm^2,~q=q_1-q_2=5-(-5)=10~nC),

so the flux is:

Φ=qSε0Scosθ=8 Vm.\Phi=\frac{qS'}{\varepsilon_0 S}\cos \theta=8~\text{V}\cdot \text{m}.

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