Question

A voltage of 200v is connected across a capacitor of capacitance of 2.5uf . calculate the charge deposited on each plate.

Answer 1

Gives

V=200v

$C=2.5\mu F$

We know that

$Q=CV$

Put value

$$Q=2.5\times10^{-6}\times200=5\times10^{-4}C=500\mu C$$

One plate charge

$Q=+500\mu C$

Another plate

$Q=-500\mu C$