Question #22060

eight equal charged drops having potential 10V are combined to form a big drop.then potential of big drop is:

Expert's answer

Condition:

Eight equal charged drops having potential 10V10\mathrm{V} are combined to form a big drop. Then potential of big drop is: _____.

Solution:

Potential of big drop = Square of cube root of number of drops ×\times potential of each of small identical drop.


Or,V=n23V.\mathrm{Or}, V' = n^{\frac{2}{3}}V.


Here, n=8n=8 and V=10V = 10 volt


V=(8)23×10=4×10=40 volt.V' = (8)^{\frac{2}{3}} \times 10 = 4 \times 10 = 40 \text{ volt}.


Answer: 40 volt.

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