Question

The uniform fields shown in Figure 5.18 are near a dielectric–dielectric boundary but on opposite sides of it. Which configurations are correct? Assume that the boundary is charge free and that epsilon 2 > epsilon 1.

Answer 1

As per the given question,

We know that $H=\sqrt{\frac{\epsilon_o}{\mu_o}}E\cos\theta$

From the above, we can conclude that $\mu_o \propto \epsilon_o$

and from the snell's rule,$\frac{\sin i}{\sin r}=\frac{\mu_2}{\mu_1}=\frac{\epsilon_1}{\epsilon_2}$

So, we can conclude that if angle of refraction is greater then medium is rarer. Hence we can say that $\epsilon_{2}>\epsilon_1$

Hence, option (a), (c), (d) and (f) is the correct answer.