Question

The relaxation time of mica (sigma = 10^-15 S/m, epsilon r = 6) is

(a) 5 x 10^-10 s

(b) 10^-6 s

(c) 5 hr

(d) 10 hr

(e) 15 hr

Answer 1

Gives

$\sigma=10^{-15}S/m \\\epsilon_r=6 \\t_r=\epsilon_0\\t_r=\frac{\epsilon_0 \epsilon_r}{\sigma}$

Put value

$t_r=\frac{8.85\times10^{-12}\times6 }{10^{-15}\times60\times60}=15hr$

Option (d) is correct option