Question #218081

a certain electromagnet consist of a solenoid 5.0cm long with 200 turns of wire wound on a soft iron core that intensifies the field 130 times find b when the current is 0.3a

Expert's answer

l=0.05m

N=200

I=0.3Aμr=130μ0=4π×107Wb/AmI=0.3A\\\mu_r=130\\\mu_0=4\pi\times10^{-7}Wb/Am

B=μ0μrniB=\mu _0\mu_rni

n=Nl=2000.05=4000n=\frac{N}{l}=\frac{200}{0.05}=4000


B=4π×107×130×4000×0.3=0.20TB=4\pi\times10^{-7}\times130\times4000\times0.3=0.20T


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