Question

A has a postive charge of 3.0x10^-6 c object b has a postive charge of 9.0 x 10^-6 c . If the distance between a and b is 0.015m what is the force

Answer 1

Using Coulomb's law

$F= k{q_1q_2\over r^2}$

$=9×10^9{(3.0×10^{-6})×(9.0×10^{-6})\over 0.015^2}$

$=1080N$