An electric induction coil of length of 10cm has 1000 turns of radius 5cm. (μ0=4π x 10-7S.I). What is the value of the inductance?
L=μ0N2Sl=μ0πN2r2l=4π2⋅10−7⋅10002⋅0.0520.1=0.1 H.L=\frac{\mu_0 N^2S}l=\frac{\mu_0\pi N^2r^2}l=\frac{4\pi^2\cdot 10^{-7}\cdot 1000^2\cdot 0.05^2}{0.1}=0.1~H.L=lμ0N2S=lμ0πN2r2=0.14π2⋅10−7⋅10002⋅0.052=0.1 H.
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