What is (a) the position, and (b) the size, of the image of a 7.60cm-high object placed 1.00 m from a +50.0-mm-focal-length camera lens?
a)
f=dFd−F=1⋅0.051−0.05=52.6 mm,f=\frac{dF}{d-F}=\frac{1\cdot 0.05}{1-0.05}=52.6~mm,f=d−FdF=1−0.051⋅0.05=52.6 mm,
b)
h=Hfd=76⋅0.05261=4 mm.h=H \frac fd=76\cdot \frac{0.0526}{1}=4~mm.h=Hdf=76⋅10.0526=4 mm.
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