Question

Find the critical angle for an air–water boundary. (The index of refraction of water is 1.33.)

Answer 1

From Snell's law we have,

a$\mu$_w = $\frac{1}{Sin(ic)}$

Sin(i_c) = $\frac{1}{aμw}$

= $\frac{1}{1.33}$

i_c = 48^o45'