Question #214399

Light travelling in air strikes a flat piece of uniformly thick glass at an incident angle of 60.0°, as shown. If the index of refraction of the glass is 1.50, (a) what is the angle of refraction θA in the glass; (b) what is the angle θB at which the ray emerges from the glass?


1
Expert's answer
2021-07-07T08:39:21-0400


According to Snell's Law

n1sinθ1=n2sinθ2n_1sin \theta_1= n_2sin \theta_2

a) When ray strikes the thick mirror

n1=1n2=1.5θ1=60oθ2=θA1×sin60=1.5×sinθAθA=35.26on_1=1 \\ n_2=1.5 \\ \theta_1=60^o \\ \theta_2=\theta_A \\ 1 \times sin60 =1.5 \times sin \theta_A \\ \theta_A =35.26^o

b) when the light emerges out from thick mirror

n1=1.5n2=1θ1=35.26oθ2=θB1.5×sin35.26=1×sinθBθB=60on_1=1.5 \\ n_2=1 \\ \theta_1=35.26^o \\ \theta_2=\theta_B \\ 1.5 \times sin 35.26=1 \times sin \theta_B \\ \theta_B= 60^o


Need a fast expert's response?

Submit order

and get a quick answer at the best price

for any assignment or question with DETAILED EXPLANATIONS!

Comments

No comments. Be the first!
LATEST TUTORIALS
APPROVED BY CLIENTS