V=3x2y−yz
V(1,0,1)=0
E=−∇V
E1,0,1=−(6(0)ax+(3×1+1)ay−0az) E=−4ay
Option (a) wrong(incorrect)
P=x2y−1
Equpotential line equation
∇.P=∇.(x2y−1)=2xyax+x2ay→(2) Equation (2) is lies xy-plane
Option (b) is correct option
Electric field
V=3x2y−yz
V(2,−1,4)=3×4(−1)−(−1)×4=−8V Option (c) is correct
E=−∇V=−(6xyax+(3x2−z)ay−yaz) E=12ax−8ay−az
Option (d) is correct
E=12ax−8ay−az
V^=∣∇V∣∇V
V^=14.56axyax+(3x2−z)ay+az(−y)
V^(2,−1,4)=14.4−12ax+14.48ay+14.41az V^=−0.83ax+0.55ay+0.07az
Option (e) is correct
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