Question

An object which is 6.0 cm tall is situated 20 cm from a converging lens of 15 cm focal length. Determine the position and nature of the image

Answer 1

$$\frac{1}{v}-\frac{1}{u}=\frac{1}{f}\\ \frac{1}{v}-\frac{1}{-20}=\frac{1}{15}\\v=60\ cm$$

Inverted, real, enlarged image.