What will be resistivity of a metal wire of 2m length and 0.6 mm in diameter, if the resistance of the wire is 50
l= 2 m
d = 0.6 mm
R= 50 Ω
Radius of wire r=0.3 mm=0.3×10−3 mr = 0.3\; mm = 0.3 \times 10^{-3} \;mr=0.3mm=0.3×10−3m
Area of cross section:
A=πr2A=3.14×(0.3×10−3)2=0.2826×10−6 m2R=ρ×lA50=ρ×20.2826×10−6ρ=50×0.2826×10−62=7.065×10−6 ΩmA = πr^2 \\ A = 3.14 \times (0.3 \times 10^{-3})^2 = 0.2826 \times 10^{-6}\;m^2 \\ R = ρ \times \frac{l}{A} \\ 50 = ρ \times \frac{2}{0.2826 \times 10^{-6}} \\ ρ = \frac{50 \times 0.2826 \times 10^{-6}}{2} = 7.065 \times 10^{-6} \;ΩmA=πr2A=3.14×(0.3×10−3)2=0.2826×10−6m2R=ρ×Al50=ρ×0.2826×10−62ρ=250×0.2826×10−6=7.065×10−6Ωm
Need a fast expert's response?
and get a quick answer at the best price
for any assignment or question with DETAILED EXPLANATIONS!
Comments