Question #210995

The back e.m.f induced in coil when electric charges from 1A to zero in millisecond is 4 volt. Find the self induction n(L) of coil.


1
Expert's answer
2021-06-29T13:04:41-0400

Gives


i2=1A,i1=0A,t=1×103sec;e=4Vi_2=1A,i_1=0A,t=1\times10^{-3}sec;e=4V

L=?

We know that

e=Ldidte=L\frac{di}{dt}

Put value

L=edidtL=\frac{e}{\frac{di}{dt}}


L=4(10)1×103=4×103HL=\frac{4}{\frac{(1-0)}{1\times10^{-3}}}=4\times10^{-3}H

L=4mHL=4mH


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