Question #205796

If a house is supplied with 120 V, 100 A service, 2400 W electric range 1000 W steam iron Ten 25W bulbs one 500W Refrigrator If all the appliances are used for 4 Hour 15 Minutes how much energy is converted in kWh? 



1
Expert's answer
2021-06-11T11:21:47-0400

Total power = Power used by all appliances.

Power=2400W+1000W+10(25W)+500WPower = 2400W +1000W+10(25W)+500W

Power=4150WPower =4150 W

Power=4.15kWPower =4.15kW

Therefore, W=Power(kW)Time(h)W= Power(kW)*Time(h)

W=PtW=Pt

W=(4.15kW)(4.25h)W=(4.15kW)(4.25h)

W=17.6375kWhW=17.6375 kWh


Need a fast expert's response?

Submit order

and get a quick answer at the best price

for any assignment or question with DETAILED EXPLANATIONS!

Comments

No comments. Be the first!
LATEST TUTORIALS
APPROVED BY CLIENTS