Question #205792

If a house is supplied with 120 V, 100 A service, find the maximum power capability. 



1
Expert's answer
2021-06-11T11:21:43-0400

P=VIP=VI

P=(120V)(100A)P=(120V)(100A)

P=12000WP=12000W

P=12kWP=12kW


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