Question #205750
  1. Two point particles separated by 6 cm have charges q1 = 14nC and q2 = -23nC, respectively. What is the magnitude of the force that each exerts on each other?





2.Two charges q1 and q2 are separated by a distance 0.02mm in the air. The force between them is 100N. What will be the force between the q1 and q2 place 0.06mm apart in the air.


1
Expert's answer
2021-06-13T07:09:35-0400

1) F=kq,q2d2=910914109231090.062|F|= \frac{kq,q_2}{d^2}=\frac{9*10^9*14*10^{-9}*23*10^{-9}}{0.06^2}

=914231090.062=\frac{9*14*23*10^9}{0.06^2}

=80.5000109N=80.5000*10^9N

=8.051014N=8.05*10^{14}N

2) F1=kq1q2d2F_1= \frac{kq_1q_2}{d^2}

100=9109(q1,q2)(0.021000)2100= \frac{9*10^9(q_1,q_2)}{(\frac{0.02}{1000})^2}

=q1q=444.41020=|q_1q_|=444.4*10^{-20}

F2=9109444.41020(0.061000)2F_2=\frac{9*10^9*444.4*10^{-20}}{(\frac{0.06}{1000})^2}

F2=11.11NF _2=11.11N




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