Question #205728

https://lh5.googleusercontent.com/Sh5cNe3GkcFZjM-vC_mi8xpwniPAB_Q3yeeY4aIMIMMZ1jEmyp8wjdCSb6MeC1bMXEztEAEpsoi6Su7SZo01p-YJWXRZ59KXl1_Ic8xmaRMIqWCzRSeEHt_JIs6ClhI7Kw=w740


1
Expert's answer
2021-06-14T09:41:09-0400

Gives

Velocity (c)=2×105m/sec2\times10^{5}m/sec

Radius (r)=1 cm =1×102m1\times10^{-2}m

We know that partical motion in circuler

mv2r=qvB\frac{mv^2}{r}=qvB

B=mvqrB=\frac{mv}{qr}

Put value


B=1.67×1027×2×1051.6×1019×102=2.1×101TB=\frac{1.67\times10^{-27}\times2\times10^5}{1.6\times10^{-19}\times10^{-2}}=2.1\times10^{-1}T

Option (D) is correct option


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