Question #204102

A wire of length 150cm carrying an electric current of 0.1A in the negative x direction and perpendicular to a magnetic field B, experiences a force of 6.0 * 10^-3 N in the positive y direction due to a magnetic field. Find:

A. The magnitude of the magnetic field.

B. Direction of the magnetic field.


1
Expert's answer
2021-06-07T09:33:34-0400

Gives

Length (L)=150cm

Current (I)=0.1A

Force (F)=6×103N6\times10^{-3}N

F=ILBF=ILB

Magnetic field

B=FLIB=\frac{F}{LI}

Put value

B=6×103150×102×0.1B=\frac{6\times10^{-3}}{150\times10^{-2}\times0.1}

Direction (i^)-\hat i)

B=0.04T


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