Question

An inductor is connected to an AC voltage source with peak voltage 35 V at 200 Hz, and the rms current is measured to be 52 mA. Calculate the inductance.

Give the value in henrys, to 2 decimal places.

Answer 1

Gives

$V_m=35V$

$n=200Hz$

$I_{RMS}=52mA$

We know that

$I_m=\frac {I_{RMS}}{\sqrt2}$

$V_m=I_mX_L$

Put value

$$35=\sqrt2\times52\times10^{-2}\times2\pi\times200\times L$$

$L=37.89\times10^{-3}$ H