Question #19995
What is the magnitude of the electric field 0.3 m from a 10-4 C point charge?
Expert's answer
the magnitude is
E=kq/r^2 = 9*10^9 N*m^(2) C^(-2) *& 10^(-4)& C / (0.3 m)^2& = 10^7 V/m
E=kq/r^2 = 9*10^9 N*m^(2) C^(-2) *& 10^(-4)& C / (0.3 m)^2& = 10^7 V/m
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#339914 on Dec 2023
#339914 on Dec 2023