Question #199677

What happens to the force between two charged metal spheres in a vacuum if the charge on each is doubled and the distance between them in multiplied by three?


1
Expert's answer
2021-05-27T17:48:06-0400

F1=kq1q2x2F_1=k\frac{q_1q_2}{x^2}


F2=k2q12q2(3x)2F_2=k\frac{2q_12q_2}{(3x)^2}


F1/F2=9/4=2.25F2=F1/2.25=0.44F1F_1/F_2=9/4=2.25\to F_2=F_1/2.25=0.44F_1 . So, the force of the interaction will decrease .


Need a fast expert's response?

Submit order

and get a quick answer at the best price

for any assignment or question with DETAILED EXPLANATIONS!

Comments

No comments. Be the first!
LATEST TUTORIALS
APPROVED BY CLIENTS