What happens to the force between two charged metal spheres in a vacuum if the charge on each is doubled and the distance between them in multiplied by three?
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Expert's answer
2021-05-27T17:48:06-0400
F1=kx2q1q2
F2=k(3x)22q12q2
F1/F2=9/4=2.25→F2=F1/2.25=0.44F1 . So, the force of the interaction will decrease .
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