Question #197964

What is the index of refraction of a medium in which light travels at 1.89x10^8m/s


1
Expert's answer
2021-05-24T16:35:27-0400

n=index of refraction

c=speed of light in a vacuum (3×108ms)(3\times10^8\frac{m}{s})

v=speed of light in the other medium(ms)(\frac{m}{s})

n=cvn=\frac{c}{v}

n=3×108ms1.89×108msn=\frac{3\times10^8\frac{m}{s}}{1.89\times 10^8\frac{m}{s}}

n=1.59n=1.59


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